#Redshift alter table column size how to#

Join (select id, sum(rows) as rows from stv_tbl_perm group by id) c on a.id=c. SELECT TRIM (name) as tablename, TRIM (pgattribute.attname) AS columnname, COUNT (1) AS size FROM svvdiskusage JOIN pgattribute ON l pgattribute.attnum-1 AND svvdiskusage.tbl pgattribute.attrelid GROUP BY 1, 2 You can read more about the two tables involved in the query here: SVVDISKUSAGE & pgattribute. Join (select sum(capacity) as total from stv_partitions where part_begin=0) as part on 1=1 Join (select id, sum(rows) as rows from stv_tbl_perm group by id) c on a.id=c.id Join (select tbl, sum(decode(unsorted, 1, 1, 0)) as unsorted_mbytes, count(*) as mbytes from stv_blocklist group by tbl) b on a.id=b.tbl Join pg_namespace as pgns on pgns.oid = pgtbl.relnamespace Join pg_class as pgtbl on pgtbl.oid = a.id Select trim(pgdb.datname) as Database, trim(pgns.nspname) as Schema, trim(a.name) as Table,Ĭ.rows, ((b.mbytes/part.total::decimal)*100)::decimal(5,3) as pct_of_total, b.mbytes, b.unsorted_mbytes This includes database name, schema name, table name, total row count, size on disk and unsorted size: - sort by row count Modified versions of one of the other answers. Postgres | public | table_data1_1 | 7 | 1 Join pg_database as pgdb on pgdb.oid = a.db_idįrom stv_blocklist group by tbl) b on a.id=b.tblĭatabase | schema | table | mbytes | rows

Join pg_namespace as pgn on pgn.oid = pgc.relnamespace it means 372 MB ? select trim(pgdb.datname) as Database, trim(pgn.nspname) as Schema,įrom ( select db_id, id, name, sum(rows) as rows from stv_tbl_perm a group by db_id, id, name ) as a Is there any alternate to find out like oracle ( from DBA_SEGMENTS )įor tble size, i have below query, but not sure about exact menaing of MBYTES. SELECT pg_size_pretty( pg_relation_size('table_name') )

#Redshift alter table column size how to#

How to find out database size, tablespace, schema size & table size ?īut below are not working in redshift ( for above version ) SELECT pg_database_size('db_name')

The combination of both results will enable you to see all the users which have alter table permissions.My redshift version is: PostgreSQL 8.0.2 on i686-pc-linux-gnu, compiled by GCC gcc (GCC) 3.4.2 20041017 (Red Hat 3.4.2-6.fc3), Redshift 1.0.735 SELECT usename FROM pg_user WHERE usesuper = 'true' You can also see all the superusers who have permissions to Alter table by running the following query: =Query to see superusers= LEFT JOIN pg_tablespace t ON t.oid = c.reltablespace LEFT JOIN pg_namespace n ON n.oid = c.relnamespace , CASE WHEN c.relkind = 'v' THEN 'view' ELSE 'table' END , pg_get_userbyid(c.relowner) AS table_owner To see all the table owners, the AND section of the WHERE clause can be removed. Kindly note that in this example, the 'sales' table is used. Therefore, to see the users with alter table permissions for a specific table, there is need to determine the owner of that specific table by running the following command:

create table t 1 (c 0 int encode lzo, c 1 bigint encode zstd, c 2 varchar ( 16) encode lzo, c 3 varchar ( 32) encode zstd) The following statement alters the compression encoding for column c0 from LZO encoding to AZ64 encoding. According to our documentation, 'The right to modify or destroy an object is always the privilege of the owner only.'. The table definition for these examples is as follows. That is, only the owner of the table, the schema owner, or a superuser can Alter a table. This is because, determining whether or not a user can alter a table, works in a similar way to that were one determines whether or not a given user can drop a table. tl dr: alter table can be run by those, and only those, who can drop table.